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The time required to perform a context switch and start an ISR: 1000 clock cycles / 500 MHz = 2e-8 seconds or 0.0000002 seconds The time required to execute each ISR: 10000 clock cycles / 500 MHz = 0.0002 seconds The time required to poll an I/O device: 500 clock cycles / 500 MHz = 1e-8 seconds or 0.00000001 seconds The total time spent on ISR execution per second: 200 interrupt requests/second * 0.0002 seconds/request = 0.04 seconds The total time spent on polling per second: (1/2000) seconds/poll * 20000 polls/second = 0.01 seconds The total CPU utilization due to interrupts: 0.04 seconds / (0.04 seconds + 0.01 seconds) = 80% The total CPU utilization due to polling: 0.01 seconds / (0.04 seconds + 0.01 seconds) = 20%
Q: NO:1 Solution
The time required to perform a context switch and start an ISR: 1000 clock cycles / 500 MHz = 2e-8 seconds or 0.0000002 seconds The time required to execute each ISR: 10000 clock cycles / 500 MHz = 0.0002 seconds The time required to poll an I/O device: 500 clock cycles / 500 MHz = 1e-8 seconds or 0.00000001 seconds The total time spent on ISR execution per second: 200 interrupt requests/second * 0.0002 seconds/request = 0.04 seconds The total time spent on polling per second: (1/2000) seconds/poll * 20000 polls/second = 0.01 seconds The total CPU utilization due to interrupts: 0.04 seconds / (0.04 seconds + 0.01 seconds) = 80% The total CPU utilization due to polling: 0.01 seconds / (0.04 seconds + 0.01 seconds) = 20%
Q: NO:2 Solution
To find the fraction of the CPU time used in interrupt handling, we can use the information provided in the question to calculate the total CPU utilization due to interrupts. We know that: The total CPU utilization due to interrupts: 0.04 seconds / (0.04 seconds + 0.01 seconds) = 80% So, 80% of the CPU time is used in interrupt handling. Or, interrupt handling uses 80/100 or 4/5 of the CPU time.