A student obtained 20% of marks and failed by 50 marks from passing marks another student obtained 40% marks and get 30 marks more than the passing marks Find the total marks in the exam:

let the maximum marks be x

Candidate A score = 20% of x

= 20/100 (x)

=> x/5

The candidate fails by 50 marks

Hence , candidate would have passed if 50 marks are added to his marks :

x/5 +50 => (x+250)/5

Now, score of Candidate B

40% of x

=> 40/100 (x) =>2x/5

A.T.Q

2xs/5 – 30

=> (2x-150)/5

both the equations are equal as both the equations justify minimum passing marks

Hence, (x+250)/5 = (2x-150)/5

cancelling 5 from both sides

x+250 = 2x – 150

x = 400

Hope this helps.