A is twice as good as a workman as B and together they finish a piece of work in 18 days. B alone will finish in how many days?

A) 27 days

B) 54 days

C) 56 days

D) 68 days

(A’s 1 day’s work) : (B’s 1 day’s work)

=2:1(A+B)‘s 1 day’s work=118A’s 1 day’s work=(118×23)=127=2:1(A+B)’s 1 day’s work=118∴A’s 1 day’s work=(118×23)=127

Hence, A alone can finish the work in 27 days.

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